x/vmware-nsx
Code Issues Proposed changes

Notify systemd when starting Neutron server

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systemd is notified only when Neutron is started with multiple api
workers. This patch adds systemd.notify_once() call when starting
Neutron server with api_workers=0

Change-Id: I95581dc5dffde6168c68d9f04cf8bdfcdb773ba8
Closes-Bug: #1330532
This commit is contained in:
Jakub Libosvar 2014-06-17 17:20:25 +02:00
parent 840425cbcb
commit 09856a0cf6
1 changed files with 2 additions and 0 deletions
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2
neutron/wsgi.py
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@ -45,6 +45,7 @@ from neutron.openstack.common import gettextutils
from neutron.openstack.common import jsonutils from neutron.openstack.common import jsonutils
from neutron.openstack.common import log as logging from neutron.openstack.common import log as logging
from neutron.openstack.common import service as common_service from neutron.openstack.common import service as common_service
from neutron.openstack.common import systemd
socket_opts = [ socket_opts = [
cfg.IntOpt('backlog', cfg.IntOpt('backlog',
@ -210,6 +211,7 @@ class Server(object):
# For the case where only one process is required. # For the case where only one process is required.
self._server = self.pool.spawn(self._run, application, self._server = self.pool.spawn(self._run, application,
self._socket) self._socket)
systemd.notify_once()
else: else:
# Minimize the cost of checking for child exit by extending the # Minimize the cost of checking for child exit by extending the
# wait interval past the default of 0.01s. # wait interval past the default of 0.01s.